Pick a Course

## How to solve questions on Time and Work under 1 Minute in GATE || Tips and Tricks

Time and Work problems are the very frequently asked in the general aptitude section of GATE. These problems can be solved easily by applying shortcuts and tricks which make them highly scoring from GATE exam perspective.

This article will highlight the shortcuts and tricks for solving problems based on time and work.

In order to assist you in your GATE preparation , We provide daily Free Quiz (chapter wise) , study tips , preparation Tips for GATE 2018 preparation .

Expert Tips and Tutorials to crack GATE 2018 Exam.

Subscribe Here

You can subscribe and get daily FREE Quiz (Chapter Wise) , study tutorials  and tips delivered on your personal email id  to crack the upcoming GATE Exam.

## Shortcuts for Solving problems based on Time and Work

#Tip1

If X can do a piece of work in n days, then X’s one day’s work = 1/n

#Tip2

If X’s one day’s work = 1/n, then X can complete the work in n days

#Tip3

If X is thrice as good a workman than Y, then Ratio of work done by X and Y= 3:1.Ratio of time taken by X and Y to complete the work = 1:3

#Tip4

More Men Can Do  More Work ;Less Men Can Do Less Work ;More men can work in  Less Time ,Less Men can work in More Time

#Tip5

M1 D1W2 = M2D2W1 where M1 men can do W1 work in D1 days and M2 men can do W2 work in D .

M1 D1 h1W2 = M2D2h2W1 where M1 men can do W1 work in D1 days for h1 hours and M2 men can do W2 work in D2 days for h2

## Solved Examples

Level : Easy

Question:         X can complete a piece of work in 18 days while Y takes 15 days to complete the same work. Y worked for 10 days and left the job. How many days would X alone take to complete the remaining work?

Solution:      Y’s 10 day’s work = (1/15) * 10 = 2/3

Remaining work = (1- 2/3) = 1/3

Now, 1/18 work is done by X in 1 day

Therefore, 1/3 work is done by X in = 18 *(1/3) = 6 days

Level : Medium

Question :   P and Q can complete a piece of work in 20 days and 12 days respectively. P started the work alone and after 4 days, Q joined him till the end of the work. How long did the work last?

Solution :    Work done by P in 4 days = (1/20) * 4 = 1/5

Remaining Work = (1- 1/5) = 4/5

(P+ Q)’s 1 day’s work = (1/20 + 1/12) = 2/15

2/15 work is done by P and Q in 1 day.

So, 4/5 work will be done by P and Q in = (4/5 * 15/2) = 6 days

Therefore, total time taken = (6+4) days = 10 days.

## Free Stimulation Mock Test For GATE 2017Start Test

Level : Difficult

Question:         X can do a certain work in same time in which Y and Z could together do it. If X and Y could together do the work in 10 days and Z alone in 50 days, how many days would Y take to complete the work alone ?

Solution:      (X + y)’s 1 day’s work = 1/10

Z’s 1 day’s work = 1/50

(x + Y+ Z)’S 1 day’s work = (1/10 + 1/50) = 3/25..........(i)

X’s 1 day’s work = (Y+ Z)’s 1 day’s work.....................(ii)

Solving (i) and (ii), we get

2 * (X’s 1 day’s work) = 3/25

Therefore, X’s 1 day’s work = 3/50

Therefore, Y’s 1 day’s work = (1/10 – 3/50) = 1/25

Therefore, Y alone can do the work in 25 days

Best Wishes!!

Free All India Test Equipped with Artificial Intelligence

Start Test